L\u00f4 xi\u00ean l\u00e0 m\u1ed9t trong s\u1ed1 nh\u1eefng h\u00ecnh th\u1ee9c ch\u01a1i s\u1ed1 ph\u1ed5 bi\u1ebfn. \u0110\u00e2y l\u00e0 c\u00e1ch \u0111\u00e1nh kh\u00e1 th\u00fa v\u1ecb v\u00e0 c\u00f3 th\u1ec3 mang l\u1ea1i hi\u1ec7u qu\u1ea3 r\u1ea5t cao n\u1ebfu ng\u01b0\u1eddi ch\u01a1i \u00e1p d\u1ee5ng nhu\u1ea7n nhuy\u1ec5n.<\/strong><\/p>\n Tr\u01b0\u1edbc khi t\u00ecm hi\u1ec3u v\u1ec1 c\u00e1ch \u0111\u00e1nh l\u00f4 xi\u00ean th\u00ec ta c\u1ea7n hi\u1ec3u kh\u00e1i ni\u1ec7m l\u00f4 xi\u00ean l\u00e0 g\u00ec.<\/p>\n L\u00f4 xi\u00ean ngh\u0129a l\u00e0 ch\u01a1i t\u1eeb 2 con l\u00f4 tr\u1edf l\u00ean c\u00f9ng l\u00fac. \u0110i\u1ec1u n\u00e0y \u0111\u1ed3ng ngh\u0129a v\u1edbi vi\u1ec7c b\u1ea1n s\u1ebd th\u1eafng khi v\u00e0 ch\u1ec9 khi t\u1ea5t c\u1ea3 s\u1ed1 l\u00f4 b\u1ea1n \u0111\u00e1nh c\u00f9ng v\u1ec1 trong 1 ng\u00e0y.<\/p>\n V\u00ec \u0111\u1ed9 kh\u00f3 cao h\u01a1n, do v\u1eady m\u00e0 l\u00f4 xi\u00ean c\u0169ng mang l\u1ea1i l\u1ee3i nhu\u1eadn cao h\u01a1n cho ng\u01b0\u1eddi ch\u01a1i. V\u1eady, x\u00e1c su\u1ea5t \u0103n l\u00f4 xi\u00ean l\u00e0 bao nhi\u00eau?<\/p>\n Ch\u1ec9 t\u00ednh ri\u00eang XSMB th\u00ec c\u00f3 27 gi\u1ea3i th\u01b0\u1edfng, t\u01b0\u1edbng \u1ee9ng kho\u1ea3ng 27 con l\u00f4 (tr\u01b0\u1eddng h\u1ee3p m\u1ed7i l\u00f4 ra 1 nh\u00e1y). V\u1eady trong t\u1ed5ng s\u1ed1 100 con s\u1ed1 t\u1eeb 00 \u2013 99, ta c\u00f3 27 s\u1ed1 n\u1eb1m trong b\u1ea3ng k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 h\u00e0ng ng\u00e0y. X\u00e1c su\u1ea5t tr\u00fang l\u00e0 27%.<\/p>\n Trong tr\u01b0\u1eddng h\u1ee3p c\u00f3 c\u00e1c l\u00f4 tr\u00f9ng nhau th\u00ec x\u00e1c su\u1ea5t h\u1ea1 xu\u1ed1ng c\u00f2n 23,7%.<\/p>\n T\u1eeb \u0111\u00e2y ta c\u00f3 c\u00f4ng th\u1ee9c t\u00ednh x\u00e1c su\u1ea5t tr\u00fang l\u00f4 xi\u00ean nh\u01b0 sau:<\/p>\n \u0110\u1ed1i v\u1edbi l\u00f4 xi\u00ean 4, x\u00e1c su\u1ea5t tr\u00fang ch\u1ec9 c\u00f3 0,32% th\u00ec \u0111i\u1ec1u n\u00e0y c\u00f3 th\u1ec3 hi\u1ec3u l\u00e0 t\u1ef7 l\u1ec7 tr\u00fang l\u00f4 xi\u00ean 4 c\u00f2n kh\u00f3 h\u01a1n tr\u00fang \u0111\u1ec1.<\/p>\n >> H\u01b0\u1edbng d\u1eabn c\u00e1ch \u0111\u00e1nh song th\u1ee7 l\u00f4 \u0111\u1ec3 tr\u00fang s\u1ed1 nh\u1ea5t ?<\/p>\n \u0110\u00e1nh 2 con l\u00f4 b\u1ea5t k\u1ef3. N\u1ebfu k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 ra 2 con l\u00f4 \u0111\u00f3 trong c\u00f9ng 1 k\u1ef3 m\u1edf th\u01b0\u1edfng th\u00ec b\u1ea1n \u0103n l\u00f4 xi\u00ean 2.<\/p>\n T\u1ef7 l\u1ec7 th\u1eafng ti\u1ec1n l\u00f4 xi\u00ean 2 th\u01b0\u1eddng l\u00e0 1 \u0103n 10.<\/p>\n V\u00ed d\u1ee5:<\/span> b\u1ea1n \u0111\u00e1nh 100.000 \u0111\u1ed3ng l\u00f4 xi\u00ean 2: 38-24 XSMB. N\u1ebfu h\u00f4m \u0111\u00f3 gi\u1ea3i l\u00f4 v\u1ec1 c\u00f3 c\u1ea3 2 s\u1ed1 l\u00f4 m\u00e0 b\u1ea1n \u0111\u00e1nh th\u00ec b\u1ea1n \u0103n: 100.000\u00d710= 1000.0000 \u0111\u1ed3ng.<\/p>\n L\u00f4 xi\u00ean 3 l\u00e0 \u0111\u00e1nh 3 con l\u00f4 b\u1ea5t k\u1ef3 trong c\u00f9ng 1 \u0111\u00e0i v\u00e0 1 ng\u00e0y m\u1edf th\u01b0\u1edfng. N\u1ebfu 3 con l\u00f4 \u0111\u00f3 c\u00f9ng ra th\u00ec b\u1ea1n \u0103n l\u00f4 xi\u00ean 3.<\/p>\n V\u1edbi \u0111\u1ed9 kh\u00f3 cao h\u01a1n so v\u1edbi l\u00f4 xi\u00ean 2, xi\u00ean 3 c\u00f3 t\u1ef7 l\u1ec7 \u0103n l\u00ean \u0111\u1ebfn 1\/40 (\u0111\u1eb7t 1 \u0103n 40)<\/p>\n V\u00ed d\u1ee5:<\/span> b\u1ea1n \u0111\u00e1nh 100.000 \u0111\u1ed3ng l\u00f4 xi\u00ean 3: 38 \u2013 24 \u2013 58 XSMB. N\u1ebfu h\u00f4m \u0111\u00f3 c\u1ea3 3 l\u00f4 c\u00f9ng v\u1ec1 th\u00ec b\u1ea1n \u0103n: 100.000\u00d740=4000.000 \u0111\u1ed3ng.<\/p>\n T\u01b0\u01a1ng t\u1ef1, l\u00f4 xi\u00ean 4 ngh\u0129a l\u00e0 \u0111\u00e1nh 4 con l\u00f4 b\u1ea5t k\u1ef3 trong c\u00f9ng 1 \u0111\u00e0i v\u00e0 1 ng\u00e0y m\u1edf th\u01b0\u1edfng. Ch\u1ec9 khi 4 con l\u00f4 \u0111\u00f3 v\u1ec1 c\u00f9ng 1 k\u1ef3 quay th\u00ec b\u1ea1n m\u1edbi tr\u00fang gi\u1ea3i.<\/p>\n \u0110\u1ed1i v\u1edbi l\u00f4 xi\u00ean 4, x\u00e1c su\u1ea5t v\u1ec1 \u0111\u1ee7 4 l\u00f4 l\u00e0 r\u1ea5t kh\u00f3. Cao th\u1ee7 n\u00e0o th\u1eafng l\u00f4 s\u1ebd \u0103n g\u1ea5p 100 l\u1ea7n s\u1ed1 v\u1ed1n. \u0110\u1eb7t 1 \u0103n 100.<\/p>\n V\u00ed d\u1ee5:<\/span> \u0111\u00e1nh 100.000 \u0111\u1ed3ng l\u00f4 xi\u00ean 4: 38 \u2013 24 \u2013 58 \u2013 63 XSMB. N\u1ebfu h\u00f4m \u0111\u00f3 v\u1ec1 \u0111\u1ee7 4 l\u00f4 th\u00ec b\u1ea1n \u0103n: 100.000\u00d7100= 10.000.000 \u0111\u1ed3ng.<\/p>\n<\/div>\n<\/p>\n
Gi\u1ea3i \u0111\u00e1p l\u00f4 xi\u00ean l\u00e0 g\u00ec ?<\/strong><\/h2>\n
X\u00c1C SU\u1ea4T \u0102N L\u00d4 XI\u00caN BAO NHI\u00caU?<\/strong><\/h3>\n
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C\u00c1C LO\u1ea0I L\u00d4 XI\u00caN \u2013 \u0110\u00c1NH L\u00d4 XI\u00caN \u0102N BAO NHI\u00caU?<\/strong><\/h3>\n
L\u00f4 xi\u00ean 2<\/strong><\/h4>\n
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L\u00f4 xi\u00ean 3<\/strong><\/h4>\n
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L\u00f4 xi\u00ean 4<\/strong><\/h4>\n
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